Question

Мише вместе с папой 42 года его брату саше вместе с папой 40 лет арсению вместе 50 лет узнай сколько лет каждому из них как эту задачу решить

Answer 1

Решение
1)42+40=82 года Миша, Саша и 2 папы
2)82-50=32 года папе
3)42-32=10 лет Мише
4)40-32=8 лет Саше

Answer 2

Solving the Problem of Ages

To solve the problem of ages for Mish, Sasha, and Arseniy, we can use a system of linear equations. Let's denote the ages of Mish, his father, and his brother as M, F, and B respectively. We are given the following information:

1. Mish and his father together are 42 years old: M + F = 42. 2. Sasha and his father together are 40 years old: S + F = 40. 3. Arseniy and his father together are 50 years old: A + F = 50.

We can solve these equations to find the ages of Mish, Sasha, and Arseniy.

Solving the Equations

We can solve these equations using substitution or elimination method. Let's use the substitution method.

From the first equation, we can express F in terms of M: F = 42 - M. Similarly, from the second equation, we can express F in terms of S: F = 40 - S. And from the third equation, we can express F in terms of A: F = 50 - A.

Now, we can substitute these expressions for F into the third equation to solve for the ages of Mish, Sasha, and Arseniy.

Substituting and Solving

Substituting F = 42 - M into the second equation, we get: M + (42 - M) = 42 42 = 42, which is always true. This means that this equation does not provide any additional information.

Substituting F = 40 - S into the second equation, we get: S + (40 - S) = 40 40 = 40, which is also always true and does not provide additional information.

Substituting F = 50 - A into the third equation, we get: A + (50 - A) = 50 50 = 50, which is always true and does not provide additional information.

Conclusion

Since all the equations are always true, we cannot uniquely determine the ages of Mish, Sasha, and Arseniy from the given information. This means that the ages of Mish, Sasha, and Arseniy cannot be uniquely determined based on the information provided.