Question

Если известно, что график функции y = kx + 2 проходит через точки a) M(– 2; 4), б) N(5; 2), то найдите значение углового коэффициента к.

Answer 1

Составим уравнение прямой, проходящей через точки
M(-2;4) N(5;2)
$\frac{y- y_{1} }{ y_{2}- y_{1} } = \frac{x- x_{1} }{ x_{2}- x_{1} }$
$\frac{y-4}{2-4} = \frac{x-(-2)}{5-(-2)}$
$\frac{y-4}{-2} = \frac{x+2}{7}$
$7(y-4)=-2(x+2)$
$7y-28=-2x-4$
$7y=-2x+24$
$y=- \frac{2}{7}x+ \frac{24}{7}$
Ответ: значение k=-2/7

Answer 2

Finding the Value of the Slope (k) for the Function y = kx^2

To find the value of the slope (k) for the function y = kx^2, we can use the given points M(–2, 4) and N(5, 2).

First, let's find the slope (k) using the given points.

The slope (k) can be found using the formula: k = (y2 - y1) / (x2 - x1)

Substitute the coordinates of points M and N into the formula to find the value of the slope (k).

Using point M(–2, 4) and N(5, 2): k = (2 - 4) / (5 - (-2))

Calculating the value of k: k = (-2) / (5 + 2) k = -2 / 7

So, the value of the slope (k) for the function y = kx^2 is -2/7.