Question

Легковая машина проходит через будет за 06:00 грузовая машина проходит этот же путь за 12:00 автомашины выехали одновременно едут навстречу друг другу через сколько часов они встретятся

Answer 1

1/6 всего пути проходит легковая за 1 час
1/12 всего пути проходит грузовая за 1 час
1/6+1/12 = 2/12+1/12 = 3/12 = 1/4 всего пути проходят вместе за 1 час.
1:1/4 = 1*4 = 4 часа - время до встречи.

Answer 2

Problem Analysis

We are given that a passenger car takes 6 hours to travel a certain distance, while a truck takes 12 hours to travel the same distance. Both vehicles start at the same time and travel towards each other. We need to determine how many hours it will take for them to meet.

Solution

To solve this problem, we can use the concept of relative speed. The relative speed between two objects moving towards each other is the sum of their individual speeds. We can calculate the relative speed between the passenger car and the truck and then use it to find the time it takes for them to meet.

Let's denote the speed of the passenger car as v1 and the speed of the truck as v2. We are given that the passenger car takes 6 hours to travel the distance, so we can calculate its speed as:

v1 = distance / time = distance / 6

Similarly, the speed of the truck can be calculated as:

v2 = distance / 12

The relative speed between the passenger car and the truck is the sum of their speeds:

relative speed = v1 + v2 = distance / 6 + distance / 12

To find the time it takes for them to meet, we can use the formula:

time = distance / relative speed

Substituting the value of the relative speed, we get:

time = distance / (distance / 6 + distance / 12)

Simplifying the expression, we get:

time = distance / (2 * distance / 12)

Canceling out the distance, we get:

time = 12 / 2 = 6 hours

Therefore, it will take 6 hours for the passenger car and the truck to meet.

Answer

The passenger car and the truck will meet after 6 hours.

Note: The sources provided do not contain relevant information for this specific problem.