Question

Диме и маме вместе 40 лет,Диме и папе-42 года,а Диме,маме и папе вместе 74 года.Сколько лет каждому.Помогите пожалуйста решить задачу.

Answer 1

74-42=32(года маме)

74-40=34(года папе)

40-32=8 или 42-34=8

Ответ:8 лет Диме

Answer 2

дима - х

мама - у

папа -z

 

 x+y=40

x+z=42

x+y+z=74 (это система)

 

 x+y=40

x+z=42

40+z=74

 

 x+y=40

x+z=42

z=34

 

 x+y=40

x+34=42

z=34

 

x+y=40

x=8

z=34

 

y=32

x=8

z=34

 

Answer 3

Problem Analysis

We are given the following information: - The sum of the ages of Dima and his mother is 40 years. - The sum of the ages of Dima and his father is 42 years. - The sum of the ages of Dima, his mother, and his father is 74 years.

We need to find the ages of each person.

Solution

Let's assume Dima's age is represented by D, his mother's age is represented by M, and his father's age is represented by F.

From the given information, we can write the following equations:

1. D + M = 40 (Equation 1) 2. D + F = 42 (Equation 2) 3. D + M + F = 74 (Equation 3)

To solve these equations, we can use a system of linear equations.

Subtracting Equation 1 from Equation 3, we get:

(D + M + F) - (D + M) = 74 - 40 F = 34 (Equation 4)

Substituting Equation 4 into Equation 2, we get:

D + 34 = 42 D = 8 (Equation 5)

Substituting Equation 5 into Equation 1, we get:

8 + M = 40 M = 32 (Equation 6)

Therefore, the ages of each person are as follows: - Dima is 8 years old. - His mother is 32 years old. - His father is 34 years old.

Conclusion

Dima is 8 years old, his mother is 32 years old, and his father is 34 years old.