Question

ПОМОГИТЕ РЕШИТЬ СИСТЕМУ УРАВНЕНИЯ!!!! х2-3у=-3 х2+3н=21

Answer 1

Х^2 - 3у = -3
+
х^2 + 3у = 21
_____
2х^2 = 18
х^2 = 9
х1 = 3; х2 = -3.

х1 = 3
х2 = -3
9 - 3у = -3

х1 = 3
х2 = -3
у = 4

Ответ: (3;4);(-3;4)

Answer 2

Домножим первое уравнение на -1:
-х2+3у=3
 х2+3у=21
---------------
6у=24
у=4
х2-12=-3
х2=9
х=3
Ответ:(3;4)

Answer 3

I can help you solve a system of equations. Your system of equations is:

$$x^2 - 3y = -3$$ $$x^2 + 3y = 21$$

To solve this system, you can use the elimination method. This method involves adding or subtracting the equations to eliminate one of the variables. Here are the steps:

1. Add the two equations to eliminate y. You get:

$$2x^2 = 18$$

2. Divide both sides by 2 to isolate x^2. You get:

$$x^2 = 9$$

3. Take the square root of both sides to find x. You get two possible values for x:

$$x = \pm \sqrt{9}$$ $$x = \pm 3$$

4. Substitute each value of x into one of the original equations and solve for y. You get two possible values for y:

When x = 3, y = 4 When x = -3, y = -4

5. Write the solutions as ordered pairs (x, y). You get two solutions for the system:

$$(3, 4)$$ $$(-3, -4)$$

You can check your solutions by plugging them into the other equation and verifying that they satisfy it.

If you want to learn more about how to solve systems of equations, you can watch some videos , , or read some articles , , , .how to solve a system of equations