Question

Вите нужно было начертить прямоугольник,длина которого 6 раз больше ширины.,Витя сделал такой чертёж:проверь правильно ли Витя выполнил задание,Вычисли периметр этого прямоугольника.

Answer 1

Если ширина -x, то длина 6x,а периметр это сумма всех сторон прямоугольника.. У прямоугольника противолежащие стороны равны, тогда. p= X+X+6X+6X==14X

Answer 2

Task: Drawing a Rectangle

Vitya needed to draw a rectangle with a length that is 6 times greater than its width. Let's verify if Vitya correctly completed the task and calculate the perimeter of this rectangle.

To determine if Vitya's drawing is correct, we need to calculate the length and width of the rectangle based on the given information. Then we can compare the proportions to see if they match.

Calculation:

Let's assume the width of the rectangle is x. According to the given information, the length of the rectangle is 6 times the width, so the length would be 6x.

To verify if Vitya's drawing is correct, we need to check if the proportions of the length and width match the given information. In this case, the length should be 6 times the width.

Therefore, the proportions should be:

Length: 6x Width: x

Perimeter Calculation:

The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, we have two sides with length 6x and two sides with length x.

The formula to calculate the perimeter of a rectangle is:

Perimeter = 2 * (Length + Width)

Substituting the values, we get:

Perimeter = 2 * (6x + x) = 2 * 7x = 14x

Therefore, the perimeter of this rectangle is 14x.

Now, let's summarize the information and calculations:

- Vitya drew a rectangle with a length that is 6 times greater than its width. - The proportions of the length and width are correct: Length = 6x, Width = x. - The perimeter of this rectangle is 14x.

Please note that the specific values of x and the actual dimensions of the rectangle are not provided in the question, so we cannot determine the exact perimeter. We can only express it in terms of x.

I hope this helps! Let me know if you have any further questions.