Question

Два токаря изготовили за смену 184 деталей. Производительность первого токаря на 3 дет/ч больше, чем второго. Сколько деталей изготовил каждый токарь за смену, если смена длится 8 ч?

Answer 1

184:8=23 (дет) изготовят два токаря за 1 час
23-3=20 (дет) 2 мастера,при одинаковой производительности
20:2=10 (дет) изготовит 1 токарь за 1 час
10+3=13 (дет) изготовит 2 токарь за 1 час
10*8=80 (дет) 1 токарь за смену
13*8=104 (дет) 2 токарь за смену
Ответ 80 деталей 1 токарь, 104 детали 2 токарь за смену

Answer 2

Problem Analysis

We are given that two lathe operators manufactured a total of 184 parts during an 8-hour shift. The productivity of the first operator is 3 parts per hour higher than that of the second operator. We need to determine how many parts each operator manufactured during the shift.

Solution

Let's assume that the second operator's productivity is x parts per hour. Therefore, the first operator's productivity would be x + 3 parts per hour.

To find the number of parts each operator manufactured, we can set up the following equation:

x * 8 + (x + 3) * 8 = 184

Simplifying the equation:

8x + 8(x + 3) = 184 8x + 8x + 24 = 184 16x + 24 = 184 16x = 160 x = 10

Therefore, the second operator manufactured 10 parts per hour, and the first operator manufactured 10 + 3 = 13 parts per hour.

To find the total number of parts manufactured by each operator during the shift, we can multiply their respective productivities by the number of hours in the shift:

Second operator: 10 parts/hour * 8 hours = 80 parts First operator: 13 parts/hour * 8 hours = 104 parts

Therefore, the second operator manufactured 80 parts, and the first operator manufactured 104 parts during the shift.

Answer

The second operator manufactured 80 parts, and the first operator manufactured 104 parts during the 8-hour shift.