Question

Найдите диагональ прямоугольного параллелепипеда, если его измерения равны 8,9,12

Answer 1

Пусть а=8,в=9 ,h=12
ABCD - основание прямоугольного параллелепипеда

Диагональ основания АС =√а²+в²=√8²+9²=√64+81=√145
Рассмотрим ΔАСА1 ⇒ СА1=√АС²+АА1²=√145+12²=√145+144=
=√289=17                                                                Ответ :  17

Answer 2

Finding the Diagonal of a Rectangular Parallelepiped

To find the diagonal of a rectangular parallelepiped with dimensions 8, 9, and 12, we can use the formula for the diagonal of a rectangular parallelepiped, which is given by:

D = √(a^2 + b^2 + c^2)

Where: - D is the diagonal length - a, b, and c are the three dimensions of the rectangular parallelepiped

Using the given dimensions: - a = 8 - b = 9 - c = 12

We can calculate the diagonal length using the formula:

D = √(8^2 + 9^2 + 12^2)

D = √(64 + 81 + 144) D = √289 D = 17

Therefore, the diagonal of the rectangular parallelepiped with dimensions 8, 9, and 12 is 17. [[3 #]]