Question

Помогите решить задачу в 1 день для детского сада купили по одинаковой цене игрушки на 6000тг а во второй день на 4800 тг .во 2 день купили на 4 игрушки меньше чем в 1 день .сколько игрушек купили в первый и во второй дни по отдельности 18 баллов даю

Answer 1

В первый день 10, а во второй 6

Answer 2

Solution for Purchasing Toys for the Kindergarten

To solve this problem, we can use a system of equations to represent the given information and then solve for the number of toys purchased on each day.

Let's denote: - x as the number of toys purchased on the first day - y as the number of toys purchased on the second day

We are given the following information: 1. The toys were purchased at the same price on both days: 6000 tenge. 2. On the second day, the toys were purchased at a lower price of 4800 tenge. 3. The number of toys purchased on the second day was 4 less than the number purchased on the first day.

We can represent this information in the form of equations and solve for the values of x and y.

Formulating the Equations

1. The total cost of toys purchased on the first day is equal to the total cost of toys purchased on the second day: - 6000x = 4800y

2. The number of toys purchased on the second day is 4 less than the number purchased on the first day: - y = x - 4

Solving the Equations

We can use the second equation to express x in terms of y and then substitute it into the first equation to solve for y.

Substitute the value of y from the second equation into the first equation: - 6000x = 4800(x - 4)

Solving for x: - 6000x = 4800x - 19200 - 1200x = 19200 - x = 16

Substitute the value of x back into the second equation to solve for y: - y = 16 - 4 - y = 12

Answer

So, the number of toys purchased on the first day is 16, and the number of toys purchased on the second day is 12.

Therefore, 16 toys were purchased on the first day, and 12 toys were purchased on the second day.

I hope this helps! If you have any further questions, feel free to ask.