Question

В 1 сосуд налили M л жидкости ,во 2 - на 7 л меньше чем в 1 , в 3 - на 10 л больше чем во 2. В 3 сосуде столько жидкости ,сколько в 1 и во 2 сосуде вместе.

Answer 1

1 сосуд - М
2 сосуд М-7
3 сосуд (М-7)+10
(М-7)+10= (М-7)+М
М+3=2М-7
2М-М=7+3
М=10 л в первом сосуде
М-7=10-7=3 л во втором сосуде
М+3=10+3=13 л в третьем сосуде

Answer 2

Problem Analysis

We are given three vessels: vessel 1 contains M liters of liquid, vessel 2 contains 7 liters less than vessel 1, and vessel 3 contains 10 liters more than vessel 2. We need to determine the total amount of liquid in vessel 3.

Solution

Let's break down the problem step by step:

1. Vessel 1 contains M liters of liquid. 2. Vessel 2 contains 7 liters less than vessel 1. Therefore, the amount of liquid in vessel 2 is (M - 7) liters. 3. Vessel 3 contains 10 liters more than vessel 2. Therefore, the amount of liquid in vessel 3 is ((M - 7) + 10) liters.

To find the total amount of liquid in vessel 3, we need to add the amounts of liquid in vessel 1 and vessel 2 together.

Calculation

The total amount of liquid in vessel 3 is given by the equation:

(M) + ((M - 7) + 10)

Simplifying the equation:

M + M - 7 + 10

2M + 3

Therefore, the total amount of liquid in vessel 3 is 2M + 3 liters.

Answer

The total amount of liquid in vessel 3 is 2M + 3 liters.

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