Question

(1\8) в степени 0,5х-1=2

Answer 1

$( \frac{1}{8})^{0,5x-1}=2 \\ (2^{-3})^{0,5x-1}=2^{1} \\ -3(0,5x-1)=1 \\ -1,5x+3=1 \\ -1,5x=-2 \\ x=1 \frac{1}{3}$