Question

В вазочке лежит 30 одинаковых по форме шоколадных конфет.Из них 15 с фруктовой начинкой и 15 со сливочной начинкой.Ване разрешили взять 2 конфеты.Какова вероятность того , что конфеты окажуться с разной начинкой?

Answer 1

Получится так, что вероятность буде равна 0,5

15/30=0,5

Answer 2

Probability of selecting two chocolates with different fillings

To calculate the probability of selecting two chocolates with different fillings, we need to consider the total number of possible outcomes and the number of favorable outcomes.

Given: - There are 30 chocolates in the box, with 15 having a fruit filling and 15 having a cream filling. - Vane is allowed to take 2 chocolates.

Total number of possible outcomes: The total number of possible outcomes is the number of ways Vane can select 2 chocolates from the box of 30. This can be calculated using the combination formula:

Total possible outcomes = C(30, 2) = 30! / (2! * (30-2)!) = 435

Number of favorable outcomes: The number of favorable outcomes is the number of ways Vane can select 2 chocolates with different fillings. Since there are 15 chocolates with a fruit filling and 15 chocolates with a cream filling, Vane can choose 1 chocolate with a fruit filling and 1 chocolate with a cream filling. This can be calculated using the product rule:

Number of favorable outcomes = 15 * 15 = 225

Probability: The probability of selecting two chocolates with different fillings is the ratio of the number of favorable outcomes to the total number of possible outcomes:

Probability = Number of favorable outcomes / Total possible outcomes = 225 / 435 ≈ 0.5172

Therefore, the probability that Vane will select two chocolates with different fillings is approximately 0.5172.