Question

Перимитр прямоугольника 56 см а одна сторона ровна 7 см найдите площадь прямоугольника

Answer 1

Ширина=(56-(7×2))÷2=21см
площадь=21×7=147 см^2

Answer 2

1)Если АВ-7см значит и СD-7 см
2)56-14(т.к. 7+7)=42 см
3)42:2=21см
АВ и СD-7cм; вс и АD-21 см
4)S= 21*7=147 cм
Вроде, так

Answer 3

Calculation of Rectangle Area and Perimeter

To find the area and perimeter of a rectangle, we need to know the length and width of the rectangle. In this case, we are given that the perimeter of the rectangle is 56 cm and one side is 7 cm. We can use this information to calculate the area of the rectangle.

Calculating the Width of the Rectangle

Let's assume the width of the rectangle is w.

The perimeter of a rectangle is given by the formula: Perimeter = 2 * (Length + Width).

We are given that the perimeter is 56 cm, so we can write the equation as: 56 = 2 * (7 + w).

Simplifying the equation: 28 = 7 + w.

Subtracting 7 from both sides of the equation: w = 28 - 7 = 21 cm.

Therefore, the width of the rectangle is 21 cm.

Calculating the Length of the Rectangle

We are given that one side of the rectangle is 7 cm, which we can assume to be the length of the rectangle.

Therefore, the length of the rectangle is 7 cm.

Calculating the Area of the Rectangle

The area of a rectangle is given by the formula: Area = Length * Width.

Substituting the values: Area = 7 cm * 21 cm = 147 cm².

Therefore, the area of the rectangle is 147 cm².

Summary

- The width of the rectangle is 21 cm. - The length of the rectangle is 7 cm. - The area of the rectangle is 147 cm².

Please let me know if there's anything else I can help you with!