Question

Растояние между двумя домами 90 метров из этих домов одновременно навстречу друг другу вышли Саша и Дима они встретились через 6 минут оказалось что Саша прошел на 60 м больше чем Дима найдите скорость каждого мальчика

Answer 1

Дима прошел s
Саша прошел s+60

Саша и Дима s + s+60 = 90
2s+60=90
2s=30
s=15
Дима прошел 15 метр
Саша прошел 15+60 =75 метр

Скорость Диму  15/6 =5/2 м/с
Скорость Сашу  75/6 =25/2 м/с



 


 

Answer 2

Problem Analysis

We are given that the distance between two houses is 90 meters. Sasha and Dima start walking towards each other from their respective houses at the same time. After 6 minutes, they meet, and it is revealed that Sasha has walked 60 meters more than Dima. We need to find the speed of each boy.

Solution

Let's assume that Sasha's speed is x meters per minute and Dima's speed is y meters per minute.

We know that the total distance covered by Sasha and Dima is 90 meters, and they meet after 6 minutes. Therefore, we can set up the following equation:

6(x + y) = 90 We are also given that Sasha has walked 60 meters more than Dima. This can be expressed as:

x = y + 60 To solve this system of equations, we can substitute the value of x from equation into equation:

6((y + 60) + y) = 90

Simplifying the equation:

6(2y + 60) = 90

12y + 360 = 90

12y = 90 - 360

12y = -270

y = -270 / 12

y = -22.5

Since speed cannot be negative, we can ignore this negative value for y.

Now, substituting the value of y into equation to find x:

x = -22.5 + 60

x = 37.5

Therefore, Sasha's speed is 37.5 meters per minute and Dima's speed is 22.5 meters per minute.

Answer

The speed of Sasha is 37.5 meters per minute and the speed of Dima is 22.5 meters per minute.