Question

У двух братьев поровну орехов. Если старший брат отдаст младшему 15 орехов, то орехов у него станет в 6 раз(-а) меньше, чем у младшего. Сколько орехов у каждого брата было первоначально?

Answer 1

Допустим первоначально у каждого брата было по "x" орехов.
Тогда:
6*(x-15)=(x+15)
6x-90=x+15
6x-x=90+15
5x=105
x=21
У первого после того,как он отдаст 15 орехов,останется 6 орехов. А у младшего соответсвенно-36 ореха.

Answer 2

Problem Analysis

We are given that two brothers initially have an equal number of nuts. If the older brother gives 15 nuts to the younger brother, the number of nuts he has will be 6 times less than the number of nuts the younger brother has. We need to determine the initial number of nuts each brother had.

Solution

Let's assume that the initial number of nuts each brother had is represented by the variables `x` and `y`, where `x` is the number of nuts the older brother had and `y` is the number of nuts the younger brother had.

According to the problem statement, we have the following information:

1. The older brother gives 15 nuts to the younger brother. 2. After giving 15 nuts, the older brother has 6 times fewer nuts than the younger brother.

Based on this information, we can set up the following equations:

Equation 1: `x - 15 = 6(y + 15)`

Equation 2: `x = y`

We can solve this system of equations to find the values of `x` and `y`.

Solution Steps

Step 1: Substitute `x` in Equation 1 with `y` from Equation 2.

Equation 1 becomes: `y - 15 = 6(y + 15)`

Step 2: Simplify and solve for `y`.

`y - 15 = 6y + 90`

`-5y = 105`

`y = -21`

Step 3: Substitute the value of `y` back into Equation 2 to find `x`.

`x = -21`

Answer

The initial number of nuts each brother had was -21. However, it is not possible to have a negative number of nuts. Therefore, there is no valid solution to this problem.

Please let me know if I can help you with anything else.