Question

{2x-y=2 / 2x^2-xy=6 теңдеулер жүйесін шығару heeeelp

Answer 1

Решение смотри в приложении

Answer 2

Solution to the System of Equations

To solve the system of equations 2x - y = 2 and 2x^2 - xy = 6, we can use various methods such as substitution, elimination, or matrix methods. Let's solve it using the substitution method.

1. Solve the first equation for y in terms of x: 2x - y = 2 y = 2x - 2.

2. Substitute the value of y in the second equation: 2x^2 - xy = 6 2x^2 - x(2x - 2) = 6 2x^2 - 2x^2 + 2x = 6 2x = 6 x = 3.

3. Substitute the value of x back into the first equation to find y: 2x - y = 2 2(3) - y = 2 6 - y = 2 y = 4.

Therefore, the solution to the system of equations 2x - y = 2 and 2x^2 - xy = 6 is x = 3 and y = 4.

Let me know if there's anything else I can help you with!