Question

Для школьной мастерской купили сначала 16 молотков а потом 20 таких же молотков.причем во второй раз заплатили на 120 рублей больше.сколько стоит один молоток.как решить задачу

Answer 1

120+16х=20х
20х-16х=120
4х=120
х=120:4
х=30(р)
 Один молоток стоит 30 рублей.

Answer 2

Problem Analysis

To solve this problem, we need to determine the cost of one hammer. We know that initially, 16 hammers were purchased, and then an additional 20 hammers were purchased, with the second purchase being 120 rubles more expensive than the first. We need to find the cost of one hammer.

Solution

Let's assume the cost of one hammer is x rubles.

The total cost of the first purchase of 16 hammers would be 16x rubles.

The total cost of the second purchase of 20 hammers would be 20x rubles.

According to the problem, the second purchase was 120 rubles more expensive than the first purchase. Therefore, we can set up the following equation:

20x = 16x + 120

To solve this equation, we can subtract 16x from both sides:

20x - 16x = 120

Simplifying the equation, we get:

4x = 120

Now, we can divide both sides of the equation by 4 to solve for x:

x = 120 / 4

Simplifying further, we find:

x = 30

Therefore, the cost of one hammer is 30 rubles.

Answer

The cost of one hammer is 30 rubles.