Question

1.1) 4 дм 6 см + 5дм 8 см =2) 8 м 5см+ 6 м 96 см=3)12км 29 м + 24 км92 м=4)2 т 4ц 56 кг+9т 6 ц 48 кг=5)3ч 48 мин + 2 ч26мин=6)25 мин 17 сек+7 мин 54 сек=2.1) 17*6 + 4*5*=*0822)253*+*79*8=4**973)8*56+*36*7+219*=6*0934)**+**=1973.зАМЕНИТЕ ЗВЕЗДОЧКИ ЦИФРАМИ ТАК, ЧТОБЫ СУММА ЛЮБЫХ ТРЁХ СОСЕДНИХ ЧИСЕЛ БЫЛА РАВНА 20:7,*,*,*,*,*,*,9.

Answer 1

1) 10дм 4 см
2) 15м 1 см
3) 36 км 121м

Answer 2

№1
1) 10 дм 4 см
2) 15 м 1 см
3) 36 км 121 м
4) 12 т 1 ц 4 кг
5) 6 ч 14 мин
6) 33 мин 11 сек
№2
1) 1726+4356=6082
2) 37958+2539=40497
3) 8256+53647+2190=64093
4) 99+98=197
№3
Рассмотрим две соседние суммы «7аб» и «аб?»,  вместо ? должна стоять цифра 7. Аналогично для двух последних сумм, 4-я цифра с конца получается 9. Ответ: 79479479

Answer 3

1.1) To solve the given equations, we need to add the given measurements. Let's convert all the measurements to the same unit before adding them.

1. 4 dm 6 cm + 5 dm 8 cm = 8 m 5 cm [[1]] 2. 8 m 5 cm + 6 m 96 cm = 15 m 1 cm [[2]] 3. 12 km 29 m + 24 km 92 m = 37 km 121 m [[3]] 4. 2 t 4 c 56 kg + 9 t 6 c 48 kg = 11 t 10 c 4 kg [[4]] 5. 3 h 48 min + 2 h 26 min = 6 h 14 min [[5]] 6. 25 min 17 sec + 7 min 54 sec = 33 min 11 sec [[6]]

2.1) To solve the given equation, we need to perform the multiplication and addition operations.

1. 17 * 6 + 4 * 5 = 122 [[7]]

2. 253 * 79 * 8 = 159,464 [[8]]

3. 8 * 56 + 36 * 7 + 219 = 2,034 [[9]]

4. To find the missing digits to make the sum of any three consecutive numbers equal to 20, we can solve the equation: 7 + x + y = 20, where x and y are the missing digits.

Solving the equation, we find that x = 6 and y = 7. Therefore, the missing digits are 6 and 7.

The equation becomes: 7, *, *, 6, 7, *, *, 9.

Note: The missing digits can be any numbers as long as their sum is 13.

5. To find the missing digits to make the sum of any three consecutive numbers equal to 20, we can solve the equation: x + y + z = 20, where x, y, and z are the missing digits.

Solving the equation, we find that x = 3, y = 8, and z = 9. Therefore, the missing digits are 3, 8, and 9.

The equation becomes: 3, 8, 2, 2, *, *, *, 9.

Note: The missing digits can be any numbers as long as their sum is 20.

Please let me know if there's anything else I can help you with!