Question

В коробке лежат одинаковые по размеру шарики: 5 зелёных,9 синих и 6 красных.Костя наугад берёт один шарик.Какова вероятность , что он будет зелёным?

Answer 1

5+9+6=20 шаров всего
вероятность зеленого шара равна 5\20 или 1\4  
числитель и знаменатель делим на 5

Answer 2

Problem Analysis

In the given problem, there are a total of 5 green balls, 9 blue balls, and 6 red balls in a box. Kostya randomly selects one ball from the box, and we need to find the probability that the ball he selects is green.

Solution

To find the probability, we need to divide the number of favorable outcomes (selecting a green ball) by the total number of possible outcomes (selecting any ball).

The total number of balls in the box is 5 (green) + 9 (blue) + 6 (red) = 20.

Therefore, the probability of selecting a green ball is given by:

Probability = Number of green balls / Total number of balls

Probability = 5 / 20

Simplifying the fraction, we get:

Probability = 1/4

So, the probability that Kostya will select a green ball is 1/4.

Answer

The probability that Kostya will select a green ball is 1/4.