Question

1) (11/24+1/6)* одна целая 3/5. 2) ( 7- 2 целая5/16 ) * 4/25 ПОЖАЛУЙСТА ПОМОГИТЕ СРОЧНО!!! ЗАРАНЕЕ СПАСИБО

Answer 1

1.
1) 11/24+1/6=11+4/24=15/24=5/3=одна целая 6/10
2)одна целая 6/10*одну целую 3/5=6/10*3/5=6*3_10*3=18/50+9/25=0,36

2.
1)7/1-2 целых 5/16=7/1-37/16=112-37/16=75/16=4,68
2)4 целых 68/100 * 4/25=468/100*4/25=468*4/100*25=1872/2500=0,74
Ответ: 1.-0,36
            2.-0,74

Answer 2

1) To solve the expression (11/24 + 1/6) * 1 3/5, we can follow the order of operations, which is commonly known as PEMDAS (Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction).

First, let's simplify the addition inside the parentheses: 11/24 + 1/6 = (11/24) + (4/24) = 15/24

Next, let's multiply the result by 1 3/5: (15/24) * 1 3/5 = (15/24) * (8/5) = (15 * 8) / (24 * 5) = 120/120 = 1

Therefore, the value of the expression (11/24 + 1/6) * 1 3/5 is 1.

2) To solve the expression (7 - 2 5/16) * 4/25, we can again follow the order of operations.

First, let's simplify the subtraction inside the parentheses: 7 - 2 5/16 = 7 - (2 * 16 + 5) / 16 = 7 - (37/16) = (112/16) - (37/16) = 75/16

Next, let's multiply the result by 4/25: (75/16) * 4/25 = (75 * 4) / (16 * 25) = 300/400 = 3/4

Therefore, the value of the expression (7 - 2 5/16) * 4/25 is 3/4.

I hope this helps! Let me know if you have any further questions.