Question

Петя ,Серёжа и Варя Собирают магниты с картинками . У Пети в два раза меньше магнитов чем у Серёжи ,и в четыре раза меньше чем у Вари . А вмести у них 154 магнита . Сколько магнитов у Пети ?

Answer 1

У Пети Х магнитов 
У Сережи 2Х магнита 
У Вари 4Х магнита 
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Х + 2Х + 4Х = 154 
7Х = 154 
Х = 22 ( магнита ) у Пети 
Ответ 22 магнита

Answer 2

Calculating the Number of Magnets for Each Person

To calculate the number of magnets each person has, we can use the information provided in the question. Let's denote the number of magnets that Peter (Петя), Sergey (Серёжа), and Varya (Варя) have as P, S, and V, respectively.

Given: - Peter has half as many magnets as Sergey: P = 0.5S - Peter has one-fourth as many magnets as Varya: P = 0.25V - The total number of magnets they have together is 154: P + S + V = 154

Solving for the Number of Magnets for Each Person

We can use these equations to solve for the number of magnets each person has.

First, let's express the number of magnets Sergey and Varya have in terms of P: - From the first given relation: S = 2P - From the second given relation: V = 4P

Substitute these expressions into the total number of magnets equation: - P + 2P + 4P = 154 - 7P = 154 - P = 22

So, Peter has 22 magnets.

Conclusion

After solving the equations, it is found that Peter has 22 magnets.