Question

Раскройте скобки и упростите выражение -(2x-3y+5)+3(x-y+4)

Answer 1

-2x+3y-5+3x-3y+12
x-5+12
x+7

Answer 2

- (2х - 3у + 5) + 3(х - у + 4) = - 2х + 3у - 5 + 3х - 3у + 12 = (3х - 2х) + (3у - 3у) + (12 - 5) = х + 7

Answer 3

I can help you with math problems. Here is how to solve this expression:

- First, distribute the negative sign to each term inside the parentheses: $$-(2x-3y+5)=-2x+3y-5$$ - Next, distribute the 3 to each term inside the parentheses: $$3(x-y+4)=3x-3y+12$$ - Then, combine the two expressions by adding the corresponding terms: $$-2x+3y-5+3x-3y+12=x+7$$ - Finally, simplify the expression by combining the like terms: $$x+7$$

The final answer is $$x+7$$. I hope this helps.Ответь+подробно.+Раскройте+скобки+и+упростите+выражение+-(2x-3y+5)+3(x-y+4)