Question

Из пункта А вышла грузовая машина со скоростью 35км/ч,а через 5часов вслед за не вышла легковая со скоростью 55км/ч и прибыла в пункт В на 3 часа раньше грузовой.Найдите расстояние АВ

Answer 1

х - время легкового авто
х+8 - время грузового авто
55х=35(х+8)
55х=35х+280
20х=280
х=280/20
х=14ч - время легкового авто
55*14=770км - расстояние

Answer 2

Х - время легковой, 35*(х+5) - расстояние грузовая, 55*х - расстояние легковая, зная что  расстояние одинаковое составим ур-е:
35*(х+5)=55*х
35х+175=55х
55х-35х=175
20х=1675
х=175:20
х=8,75
35* 13,75=55*8,75
481,25=481,25

8,75*55=481,25 (км) - расстояние между городами

Answer 3

Problem Analysis

We are given that a truck leaves point A with a speed of 35 km/h, and after 5 hours, a car leaves point A with a speed of 55 km/h. The car arrives at point B 3 hours earlier than the truck. We need to find the distance between points A and B.

Solution

Let's assume the distance between points A and B is d km.

The truck travels for 5 hours at a speed of 35 km/h, so the distance it covers is 35 km/h * 5 h = 175 km.

The car arrives at point B 3 hours earlier than the truck, so it takes the car (5 - 3) = 2 hours to cover the same distance. The car's speed is 55 km/h, so the distance it covers is 55 km/h * 2 h = 110 km.

The total distance between points A and B is the sum of the distances covered by the truck and the car: d = 175 km + 110 km = 285 km.

Therefore, the distance between points A and B is 285 km.

Answer

The distance between points A and B is 285 km.