Question

Два самолета вылетели одновременно навстречу друг другу из двух городов,расстояние между котороми 20310км.Первый самолет летел со скоростью 450км/ч и пролетел до встречи 1350км.С какой скоростью летел второй самолет?

Answer 1

Время полета до момента встречи 1350/450=3 ч.
До момента встречи самолеты сближаются. Найдем скорость сближения. 2310/3 = 770 км/ч.
 На долю первого самолета приходится 450 км/ч. Найдем скорость второго.770-450=320 км/ч.

Answer 2

1)1350:40 равно3( ч) 2)2310-1350 равно960( км) 3)960:3 равно 320( км/ч)- летел второй самолет ✈

Answer 3

Problem Analysis

We are given that two planes took off simultaneously from two cities and flew towards each other. The distance between the cities is 20310 km. The first plane flew at a speed of 450 km/h and traveled 1350 km before the meeting. We need to find the speed of the second plane.

Solution

To find the speed of the second plane, we can use the formula:

Speed = Distance / Time

Let's calculate the time it took for the first plane to travel 1350 km:

Time = Distance / Speed = 1350 km / 450 km/h = 3 hours

Since both planes took off simultaneously and met after 3 hours, the second plane also flew for 3 hours. Now, we can calculate the speed of the second plane:

Speed = Distance / Time = 20310 km / 3 hours = 6770 km/h

Therefore, the second plane flew at a speed of 6770 km/h.