Question

Токарь и его ученик вместе за 1ч производят 60 деталей. С какой производительностью в час работает каждый из них, если производительность токаря в 3 раза больше, чем производительность ученика. Можно без х?

Answer 1

60 поделить на 4 будет 15 получается что ученик сделал 15 деталей .
Чтоб найти токаря надо 60-15 равно 45 деталей зделал токарь.
Ответ : ученик сделал 15 деталей, а токарь 45

Answer 2

Calculation of Productivity

To calculate the productivity of the lathe operator and the apprentice, we need to determine the individual productivity of each worker. Let's assume the productivity of the apprentice is represented by x (in terms of the number of parts produced per hour). Given that the productivity of the lathe operator is three times that of the apprentice, the productivity of the lathe operator can be represented as 3x.

According to the information provided, the lathe operator and the apprentice together produce 60 parts in 1 hour. We can set up the following equation to represent this:

x + 3x = 60

Simplifying the equation, we get:

4x = 60

Now, we can solve for x to find the productivity of the apprentice:

x = 60/4 = 15

Therefore, the productivity of the apprentice is 15 parts per hour. Since the productivity of the lathe operator is three times that of the apprentice, the productivity of the lathe operator is:

3x = 3 * 15 = 45

Hence, the productivity of the lathe operator is 45 parts per hour.

Therefore, the lathe operator works at a productivity of 45 parts per hour, while the apprentice works at a productivity of 15 parts per hour.