Question

Запишите в виде суммы двух обыкновенных дробей обыкновенную дробь: 9/13 , 6/17

Answer 1

9+6/221 вот))))))))))))))

Answer 2

I can help you with your math question.

To write an ordinary fraction as a sum of two ordinary fractions, you can use the method of undetermined coefficients. The denominator of the original fraction consists of two factors. Then you can write the original fraction as two fractions: the numerator of the first fraction is denoted by A, and the denominator is the first of the factors of the main fraction. The numerator of the second fraction is denoted by B, and the denominator is the second of the factors of the main fraction. Add the fractions in the right part. The result is equal to the main fraction. This equation will be an identity if the coefficients of the same unknowns in the left and right parts are equal. We make a system of equations and find the unknown numerators A and B. Now we can write the original fraction as a sum of two fractions.

For example, let's write the fraction $$\frac{9}{13}+\frac{6}{17}$$ as a sum of two fractions. The denominator of this fraction is $$13 \cdot 17$$, so we can write: $$\frac{9}{13}+\frac{6}{17}=\frac{A}{13}+\frac{B}{17}$$

Adding the fractions on the right, we get: $$\frac{9}{13}+\frac{6}{17}=\frac{17A+13B}{13 \cdot 17}$$

Comparing the numerators, we get the system of equations: $$\begin{cases} 17A+13B=9 \\ 13A+17B=6 \end{cases}$$

Solving this system, we find: $$A=-3, B=4$$

Therefore, the fraction $$\frac{9}{13}+\frac{6}{17}$$ can be written as a sum of two fractions: $$\frac{9}{13}+\frac{6}{17}=\frac{-3}{13}+\frac{4}{17}$$

You can learn more about this method from [this video](https://www.youtube.com/watch?v=ytKmFF9ZwgY) or [this lesson](https://infourok.ru/konspekt-uroka-po-matematike-preobrazovanie-drobi-v-vide-summi-drobey-3975840.html).