Question

Периметр прямоугольника равен 96 метров и он в 8 раз больше одной из сторон прямоугольника Найдите площадь прямоугольника

Answer 1

96/8=12 м - сторона а прямоуг.
b=96/2-12=36 м - сторона b
S=a*b=12*36=432м2
Ответ: площадь прямоугольника 432м2

Answer 2

Problem Analysis

We are given that the perimeter of a rectangle is 96 meters, and it is 8 times larger than one of its sides. We need to find the area of the rectangle.

Solution

Let's assume the length of the rectangle is L and the width is W.

We are given that the perimeter of the rectangle is 96 meters. The formula for the perimeter of a rectangle is P = 2(L + W). Substituting the given value, we have:

96 = 2(L + W)

We are also given that the rectangle is 8 times larger than one of its sides. Let's assume the width is the smaller side. So, we have:

L = 8W

Now, we can substitute the value of L in terms of W into the perimeter equation:

96 = 2(8W + W)

Simplifying the equation:

96 = 2(9W)

96 = 18W

Dividing both sides by 18:

W = 96/18 = 5.33

Now, we can substitute the value of W back into the equation L = 8W:

L = 8(5.33) = 42.67

So, the width of the rectangle is approximately 5.33 meters and the length is approximately 42.67 meters.

Calculating the Area

The formula for the area of a rectangle is A = L * W. Substituting the values we found:

A = 42.67 * 5.33

Calculating the area:

A ≈ 227.03

Therefore, the area of the rectangle is approximately 227.03 square meters.

Answer

The area of the rectangle is approximately 227.03 square meters.