Question

Из пунктов А и B,расстояние между которыми 8 км,одновременно и в одном направлении вышли:из пункта А-автобус,а из B-пешеход.Найдите скорость автобуса,если он догнал пешехода,который шёл со скоростью 4 км/ч,через 1/4часа. помогите пожалуйста

Answer 1

4*1/4=1км прощел пешеход
8+1=9км-проехал автобус
9:1/4=9*4=36км/ч скорость автобуса

Answer 2

Problem Analysis

We are given that two points, A and B, are 8 km apart. An bus starts from point A and a pedestrian starts from point B. The pedestrian is walking at a speed of 4 km/h. After 1/4 hour, the bus catches up to the pedestrian. We need to find the speed of the bus.

Solution

Let's assume the speed of the bus is v km/h.

We know that the distance traveled by an object is equal to the product of its speed and time. Therefore, the distance traveled by the bus in 1/4 hour is (1/4)v km.

Since the bus catches up to the pedestrian, the distance traveled by the bus must be equal to the distance traveled by the pedestrian. Therefore, we can set up the following equation:

(1/4)v = 4

To find the value of v, we can solve this equation.

Calculation

Let's solve the equation to find the value of v:

(1/4)v = 4

Multiplying both sides of the equation by 4:

v = 16

Therefore, the speed of the bus is 16 km/h.

Answer

The speed of the bus is 16 km/h.