Question

Порученное задание первый рабочий выполняет за 3 часа,второй-за 6 часов.За сколько часов они выполнят задание,если будут работать вместе?

Answer 1

Первый рабочий выполняет 100% работы за 3 часа, а второй - только 50% работы. Вместе за 3 часа они сделают 150% работы, а 100% работы, т.е. всю работу, они сделают за 3ч - 1/3 = 150% - 1/3, в итоге будет 2 часа за 100% задания. 

Answer 2

Скорость первого х, второго у, а объём работы
время первого Т1=а/х=3ч, второго Т2=а/у=6ч;
вместе скорость двух рабочих х+у;
искомое время $T= \frac{a}{x+y}= \frac{ \frac{a}{a} }{ \frac{x}{a} + \frac{y}{a} }= \frac{1}{ \frac{1}{T_{1}} + \frac{1}{T_{2}} } =\\ = \frac{1}{ \frac{T_{2}+T_{1}}{T_{1}*T_{2}} }= \frac{T_{1}*T_{2}}{T_{1}+T_{2}}= \frac{6*3}{6+3}=\\ = \frac{18}{9}=2$



Ответ: 2 часа

Answer 3

Для решения данной задачи, мы можем использовать формулу, которая позволяет нам вычислить время, за которое два рабочих выполнят задание вместе. Формула выглядит следующим образом:

Время, затраченное на выполнение задания вместе = (1 / (1 / время, затраченное первым рабочим) + 1 / (время, затраченное вторым рабочим))

В данном случае, первый рабочий выполняет задание за 3 часа, а второй рабочий выполняет задание за 6 часов. Подставим эти значения в формулу:

Время, затраченное на выполнение задания вместе = (1 / (1 / 3) + 1 / 6)

Выполним вычисления:

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