Question

Два автомобиля одновременно выехали из двух городов навстречу друг другу и встретились через 2.5 часа.Расстояние между городами 375 км. найди скорости автомобилей если один из них едет на 10 км. в час быстрее другого

Answer 1

1) 375 :2,5 =150 км /час - общая скорость

Х км/час - скорость одного, ( Х +10 ) км/час - скорость другого

 х+  х+10 =150

2Х = 140

Х = 70 км/час                     70 +10 =  80 км/час  

Answer 2

Problem Analysis

We have two cars that start from two different cities and travel towards each other. They meet after 2.5 hours, and the distance between the cities is 375 km. We need to find the speeds of the two cars, given that one car is traveling 10 km/h faster than the other.

Solution

Let's assume the speed of the slower car is x km/h. Then the speed of the faster car would be x + 10 km/h.

We can use the formula distance = speed × time to calculate the speeds of the two cars.

The distance traveled by the slower car in 2.5 hours is x × 2.5 km.

The distance traveled by the faster car in 2.5 hours is (x + 10) × 2.5 km.

Since the total distance between the cities is 375 km, we can set up the following equation:

x × 2.5 + (x + 10) × 2.5 = 375

Simplifying the equation:

2.5x + 2.5(x + 10) = 375

2.5x + 2.5x + 25 = 375

5x + 25 = 375

5x = 350

x = 70

Therefore, the speed of the slower car is 70 km/h and the speed of the faster car is 80 km/h.

Answer

The speed of the slower car is 70 km/h and the speed of the faster car is 80 km/h.