Question

Hellllpppp pleeaasssseee sin 2x = 1 2x =п/2+-2пN х=п/4+-пN

Answer 1

Решение внизу на фото

Answer 2

It seems like you're trying to solve the equation sin(2x) = 1. You're on the right track, but there is a mistake in your solution. Let me help you solve it correctly.

To solve sin(2x) = 1, you need to find the values of x that satisfy this equation. Keep in mind that the sine function has a maximum value of 1, which occurs at certain points on the unit circle.

1. Start by isolating sin(2x) on one side of the equation:

   sin(2x) = 1

2. To find the values of x, you can use the inverse sine function (also known as arcsin or sin^(-1)). Take the inverse sine of both sides:

   2x = arcsin(1)

3. arcsin(1) is equal to π/2, so you have:

   2x = π/2

4. Now, isolate x by dividing both sides by 2:

   x = (π/2) / 2

5. Simplify the right side:

   x = π/4

So, the solutions to the equation sin(2x) = 1 are:

x = π/4 + πn, where n is an integer.

These are the values of x that make sin(2x) equal to 1.