Question

Вычислите: 1) log₂√ 2 2) log₂1/ ⁴√ 2 Срочно. Заранее спасибо!!!!!!!!!

Answer 1

Log₂√2 = log₂2¹/² = ¹/₂log₂2 = ¹/₂ * 1 = ¹/₂

log₂ ¹/₄ · √2 = log₂(2⁻² * 2¹/²) = log₂2⁻²⁺¹/² = log₂2⁻³/² = - ³/₂ log₂2 = -³/₂ * 1 = -³/₂ =
= -1 ¹/₂

Answer 2

1) Вычислим log₂√2: log₂√2 = log₂(2^(1/2)) = 1/2

2) Вычислим log₂(1/⁴√2): log₂(1/⁴√2) = log₂(2^(-1/4)) = -1/4

Таким образом, ответы: 1) log₂√2 = 1/2 2) log₂(1/⁴√2) = -1/4