Question

В олимпиаде по математике приняли участие 700 школьников. Во второй тур прошли 3/10 всех школьников, а 30% прошедших во второй тур стали победителями, и для награждения были объединены в группы по 7 человек в каждой. Сколько групп для награждения было на олимпиаде?

Answer 1

700*3/10=70*3=210- прошли во 2й тур

210*30/100=21*3=63- стали победителями

63:7=9 групп

Answer 2

Calculation of the Number of Groups for Awarding in the Math Olympiad

To determine the number of groups for awarding in the math olympiad, we need to follow the given information step by step.

1. The total number of participants in the math olympiad is 700. 2. In the second round, 3/10 of all the participants advanced to the next round. To calculate this, we can multiply the total number of participants by 3/10: - Number of participants in the second round = 700 * 3/10 = 210. 3. Out of the participants who advanced to the second round, 30% became winners. To calculate this, we can multiply the number of participants in the second round by 30/100: - Number of winners = 210 * 30/100 = 63. 4. The winners are grouped for the award ceremony, with 7 participants in each group. - Number of groups for awarding = Number of winners / Number of participants in each group = 63 / 7 = 9 groups.

Therefore, there were 9 groups for awarding in the math olympiad.