Question

S(t)=2t^2 +3t-1V-? a-? t=2c​

Answer 1

$s(t)=2t^2 +3t-1$

Скорость есть первая производная от координаты:

$v(t)=s'(t)=(2t^2+3t-1)'=2\cdot2t+3=4t+3$

$v(2)=4\cdot2+3=11$

Ускорение есть вторая производная от координаты или первая производная от скорости:

$a(t)=v'(t)=(4t+3)'=4$

$a(2)=4$

Answer 2

It looks like you have given a function S(t) in terms of t, and you want to find its value at t = 2. To do this, simply substitute t = 2 into the expression for S(t):

S(2) = 2(2^2) + 3(2) - 1

Now, calculate each term:

S(2) = 2(4) + 6 - 1

Simplify:

S(2) = 8 + 6 - 1

S(2) = 14 - 1

S(2) = 13 V

So, when t = 2, S(t) equals 13 V.