Question

Одну сторону квадрата увеличили на 9 см, а другую уменьшили в 5 раз. В результате получили прямоугольник, периметр которого равен 66 см. У какой фигуры квадрата или у прямоугольника- ПЛОЩАДЬ больше? На сколько?

Answer 1

P=(x+9+x/5)*2 66=(x+9+x/5)*2 33=x+9+x/5 24=1.2x x=20 S квадрата =20*20=400 Sпрямоуг=(20+9)*20/5=116 400+116=284

Answer 2

Problem Analysis

We are given a square where one side has been increased by 9 cm, while the other side has been decreased by 5 times. The resulting shape is a rectangle with a perimeter of 66 cm. We need to determine whether the area of the square or the rectangle is larger, and by how much.

Solution

To solve this problem, we need to find the dimensions of the rectangle and the square, and then compare their areas.

Let's assume that the side length of the square is x cm. According to the problem, one side of the square has been increased by 9 cm, so the length of one side of the resulting rectangle is x + 9 cm. The other side of the square has been decreased by 5 times, so the width of the resulting rectangle is x / 5 cm.

We know that the perimeter of a rectangle is given by the formula: perimeter = 2 * (length + width). In this case, the perimeter of the rectangle is given as 66 cm. Substituting the values we have, we can write the equation:

66 = 2 * (x + 9 + x / 5)

Now, let's solve this equation to find the value of x.

Solving the Equation

To solve the equation, we can start by simplifying it:

**66 = 2 * (x