Question

1) (2x + 7y – 44 = 0,2x – Зу = -36;​

Answer 1

2х+7у-44=0
2х-3у=-36. *(-1)

2х+7у=44
-2х+3у=36

10у=80
2х+7у=44

У=8
Х=-6

Answer 2

It looks like you have a system of two linear equations with two variables, x and y. You can solve this system of equations using either the substitution method or the elimination method. I'll show you how to use the elimination method:

Given equations:

1. 2x + 7y - 44 = 0
2. 2x - 3y = -36

To eliminate one of the variables, you can subtract equation (2) from equation (1) because it will eliminate the x term:

(2x + 7y) - (2x - 3y) = (0) - (-36)

Now, simplify:

2x + 7y - 2x + 3y = 0 + 36

The 2x and -2x terms cancel out:

10y = 36

Now, solve for y:

y = 36 / 10 y = 18 / 5 y = 3.6

Now that you have the value of y, you can substitute it into either of the original equations to find the value of x. Let's use equation (1):

2x + 7(3.6) - 44 = 0

2x + 25.2 - 44 = 0

2x - 18.8 = 0

Now, add 18.8 to both sides to isolate x:

2x = 18.8

Now, divide both sides by 2 to solve for x:

x = 18.8 / 2 x = 9.4

So, the solution to the system of equations is: x = 9.4 y = 3.6