Question

(4х+1)(4х-3)=9 хелпПпп

Answer 1

(4х+1)(4х-3)=9

ответ: х= 1±√13/4

Answer 2

Ответ:

4х*4х-(4х*3)+1*4х-3*1=16х-12х+4х-3=4х+4х-3=8х-3=9

8х-3=9

8х=9+3

8х=12

Х=12:8

Х=4:3( записать дробью)

Answer 3

To solve the equation (4x + 1)(4x - 3) = 9, follow these steps:

1. Expand the left side of the equation:

(4x + 1)(4x - 3) = 9

Use the FOIL method (First, Outer, Inner, Last) to expand the product:

16x^2 - 12x + 4x - 3 = 9

2. Combine like terms:

16x^2 - 8x - 3 = 9

3. Move the constant term (9) to the left side of the equation by subtracting it from both sides:

16x^2 - 8x - 3 - 9 = 0

4. Simplify the equation:

16x^2 - 8x - 12 = 0

5. Divide the entire equation by 4 to simplify it further:

4(4x^2 - 2x - 3) = 0

6. Now, we have a quadratic equation that can be factored or solved using the quadratic formula. In this case, it can be factored:

4(4x^2 - 2x - 3) = 0

4(2x - 3)(2x + 1) = 0

7. Now, set each factor equal to zero and solve for x:

2x - 3 = 0

2x = 3

x = 3/2

and

2x + 1 = 0

2x = -1

x = -1/2

So, the solutions to the equation (4x + 1)(4x - 3) = 9 are x = 3/2 and x = -1/2.