Question

(2х-1)(3х+1)+х(1-2х)=0

Answer 1

Здесь нужно решать относительно x

Answer 2

It looks like you have a quadratic equation there. Let's solve it step by step.

The given equation is:

(2x - 1)(3x + 1) + x(1 - 2x) = 0

First, let's simplify each term within the parentheses:

(6x^2 + 2x - 3x - 1) + (x - 2x^2) = 0

Now, combine like terms:

6x^2 - x - 1 + x - 2x^2 = 0

Simplify further:

4x^2 - 1 = 0

Now, we have a quadratic equation in standard form:

4x^2 - 1 = 0

To solve for x, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

In this case, the coefficients are: a = 4 b = 0 (since there's no x term) c = -1

Plugging these values into the quadratic formula:

x = (± √(0² - 4 * 4 * -1)) / (2 * 4) x = (± √(16)) / 8 x = (± 4) / 8 x = ± 0.5

So, the solutions for the equation are x = 0.5 and x = -0.5.