Question

5^2-3x -1>=0 2-3x это степень

Answer 1

5^(2-3x)-1≥0
5^(2-3x)≥1
5^(2-3x)≥5^0
2-3x≥0
-3x≥-2
x≤2/3
(-∞,2/3]

Answer 2

It seems there might be a little confusion in your question, but I'll do my best to help you out. The expression you've provided is:

5^2 - 3x - 1 >= 0

The term "2-3x" you mentioned doesn't appear in the original expression, but I'll help you solve the inequality as presented.

Step 1: Simplify the expression on the left side: 25 - 3x - 1 >= 0 24 - 3x >= 0

Step 2: Add 3x to both sides of the inequality: 24 >= 3x

Step 3: Divide both sides by 3 (remember to flip the inequality when dividing by a negative number): 8 >= x

So, the solution for the inequality is x ≤ 8. In interval notation, this would be (-∞, 8].

If you have further clarification or if you meant something different, please provide more context or details so I can assist you more accurately.