Question

3) 4 3\8+(-1\4); 3 3\8 + (-9 2\1); 3 2\15+(-9 1\3);

Answer 1

4 3\8+(-1\4)=4 3/8-1/4=4 3/8-2/8=4 1/8

3 3\8 + (-9 2\1)=3 3/8-9 1/2=3 3/8-

9 4/8=-6 1/8

3 2\15+(-9 1\3)=3 2/15-9 1/3=3 2/15-

9 5/15=-6 1/5

Answer 2

To solve these expressions, we need to perform the addition or subtraction of the mixed numbers. Remember that when adding or subtracting mixed numbers, we need to first convert them to improper fractions, perform the operation, and then simplify the result back to a mixed number if necessary.

1. $4 \frac{3}{8} + \left(-1 \frac{1}{4}\right)$:

Step 1: Convert the mixed numbers to improper fractions. $4 \frac{3}{8} = \frac{4 \times 8 + 3}{8} = \frac{35}{8}$

$-1 \frac{1}{4} = \frac{-1 \times 4 + 1}{4} = \frac{-3}{4}$

Step 2: Perform the addition. $\frac{35}{8} + \left(-\frac{3}{4}\right) = \frac{35}{8} - \frac{3}{4}$

Step 3: Find a common denominator, which is 8 in this case. $\frac{35}{8} - \frac{3}{4} = \frac{35}{8} - \frac{6}{8}$

Step 4: Perform the subtraction. $\frac{35}{8} - \frac{6}{8} = \frac{35 - 6}{8} = \frac{29}{8}$

Step 5: Simplify the result to a mixed number, if necessary. $\frac{29}{8} = 3 \frac{5}{8}$

So, $4 \frac{3}{8} + \left(-1 \frac{1}{4}\right) = 3 \frac{5}{8}$

2. $3 \frac{3}{8} + \left(-9 \frac{2}{1}\right)$:

Step 1: Convert the mixed numbers to improper fractions. $3 \frac{3}{8} = \frac{3 \times 8 + 3}{8} = \frac{27}{8}$

$-9 \frac{2}{1} = -9 \times 1 + 2 = -7$

Step 2: Perform the addition. $\frac{27}{8} + (-7) = \frac{27}{8} - 7$

Step 3: Find a common denominator, which is 8 in this case. $\frac{27}{8} - 7 = \frac{27}{8} - \frac{56}{8}$

Step 4: Perform the subtraction. $\frac{27}{8} - \frac{56}{8} = \frac{27 - 56}{8} = \frac{-29}{8}$

Step 5: Simplify the result to a mixed number, if necessary. $\frac{-29}{8} = -3 \frac{5}{8}$

So, $3 \frac{3}{8} + \left(-9 \frac{2}{1}\right) = -3 \frac{5}{8}$

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