Question

Уравнение...1) (396+×)+35=19352) (840-×)+19=3723) (1600-×)+38=2005

Answer 1

Ответ:х=1539

Х=1212

Х=405

Пошаговое объяснение:

Answer 2

To solve each of these equations, we need to isolate the variable (let's call it "x") on one side of the equation. We can do this by performing inverse operations to eliminate any constants or terms attached to the variable.

Let's solve each equation step by step:

1. (396 + x) + 35 = 1935

Step 1: Combine like terms on the left side of the equation. 396 + x + 35 = 1935

Step 2: Combine constants on the left side. 431 + x = 1935

Step 3: Isolate the variable by moving 431 to the other side of the equation. x = 1935 - 431

Step 4: Simplify the right side. x = 1504

So, the solution to the first equation is x = 1504.

2. (840 - x) + 19 = 372

Step 1: Combine like terms on the left side of the equation. 840 - x + 19 = 372

Step 2: Combine constants on the left side. 859 - x = 372

Step 3: Isolate the variable by moving 859 to the other side of the equation. -x = 372 - 859

Step 4: Simplify the right side. -x = -487

Step 5: To solve for x, multiply both sides by -1 (to get rid of the negative sign in front of x). x = 487

So, the solution to the second equation is x = 487.

3. (1600 - x) + 38 = 2005

Step 1: Combine like terms on the left side of the equation. 1600 - x + 38 = 2005

Step 2: Combine constants on the left side. 1638 - x = 2005

Step 3: Isolate the variable by moving 1638 to the other side of the equation. -x = 2005 - 1638

Step 4: Simplify the right side. -x = 367

Step 5: To solve for x, multiply both sides by -1. x = -367

So, the solution to the third equation is x = -367.