Question

-3<1+2х<7 пж срочнооооооооооооо​

Answer 1

-3 < 1+2x < 7 |-1

-3-1 < 2x < 7-1

-4 < 2x < 6 |:2

-2 < x < 3

Ответ: (-2; 3)

Answer 2

Ответ:

-3<1+2х<7;

-4<2х<6;

-2<х<3

Ответ: (-2;3)

Пошаговое объяснение:

Вначале отнимаем от всех частей единицу, а потом делим на два

Answer 3

To solve the inequality -3 < 1 + 2x < 7, we need to find the range of values for x that satisfy this inequality. Let's break it down into two separate inequalities:

1. -3 < 1 + 2x
2. 1 + 2x < 7

Now, solve each inequality separately:

1. -3 < 1 + 2x

Subtract 1 from both sides: -4 < 2x

Divide both sides by 2 (since 2 is positive, the inequality sign remains the same): -2 < x

2. 1 + 2x < 7

Subtract 1 from both sides: 2x < 6

Divide both sides by 2 (since 2 is positive, the inequality sign remains the same): x < 3

So, combining the two inequalities, we have:

-2 < x < 3

Therefore, the solution for the original inequality is -2 < x < 3.