Question

2a^2+3a+1=0 плизззззз​

Answer 1

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$x_{12} =-b$±$\sqrt{D} /2a$

$x_{1} =-3+1/4=-1/2$

$x_{2} =-3-1/4=-1$

Ответ: -1; -1/2

Answer 2

To solve the quadratic equation 2a^2 + 3a + 1 = 0, we can use the quadratic formula:

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In your case, a = 2, b = 3, and c = 1. Substituting these values into the quadratic formula:

x = (-(3) ± √((3)^2 - 4(2)(1))) / 2(2) x = (-3 ± √(9 - 8)) / 4 x = (-3 ± √1) / 4

Now, there are two solutions for x:

1. x = (-3 + 1) / 4 = -2 / 4 = -1/2
2. x = (-3 - 1) / 4 = -4 / 4 = -1

So, the solutions to the equation 2a^2 + 3a + 1 = 0 are a = -1/2 and a = -1.