
2,7 х – 8,1y = 11,8,16x - 15y = 1;


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It seems like you've provided a system of two equations with two variables:
Equation 1: 2.7x - 8.1y = 11.8 Equation 2: 16x - 15y = 1
To solve this system of equations, you can use methods such as substitution or elimination. I'll demonstrate the elimination method here:
First, let's make the coefficients of one of the variables the same in both equations. Let's choose to eliminate the y variable. Multiply both sides of Equation 1 by 15 and Equation 2 by 8.1 to match the coefficients of y:
Equation 1 (multiplied by 15): 40.5x - 121.5y = 177 Equation 2 (multiplied by 8.1): 129.6x - 121.5y = 8.1
Now, subtract Equation 2 from Equation 1 to eliminate the y variable:
(40.5x - 121.5y) - (129.6x - 121.5y) = 177 - 8.1 -89.1x = 168.9 x = -168.9 / 89.1 x = -1.89
Now that we have the value of x, we can substitute it back into Equation 2 to solve for y:
16x - 15y = 1 16(-1.89) - 15y = 1 -30.24 - 15y = 1 -15y = 31.24 y = -31.24 / 15 y = -2.0827
So, the solution to the system of equations is approximately: x ≈ -1.89 y ≈ -2.0827


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