Вопрос задан 11.07.2023 в 10:07. Предмет Математика. Спрашивает Авраменко Дима.

{2(x+y)-x+6=0, {4(x+y)-3x-23=0; Помогите решить)

Смотреть ответ alexey08046 alexey08046 Ответ: {5у-2х=23. {5у-2х=23 {2у+3х=-6. {-5у-7,5х=15 -9,5х=38 {х=-4 {2у+3×(-4)=-6 {х=-4 {2у=6 х=-4; у=3 Пошаговое объяснение: Новые вопросы в Математика хелп меее плсразвернутыйотет нада​ 0,9/0,09=столбик пожалуйста помогите 17/0,17 =в столбик пж помогите знайти екстремули функції а)y=2x³-3x²б)y=x+2/x²+5​ ПОМОГИТЕ ПЖ Я АР СДАЮ!(4. Задание.Система команд исполнителя "Утроитель"включает команды:1. умножить число на 3;2.прибавить к числу 2.Можно ли с помощ … ью данного исполнителя получить:1. из числа 3 число 30;2. из числа 4 число 48?Ответ обоснуйте. Если алгоритмы существуют, то приведите наиболее короткий из возможных алгоритмов.​ Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Для решения системы уравнений {2(x+y)-x+6=0, {4(x+y)-3x-23=0, давайте сначала выразим одну из переменных из первого уравнения и подставим во второе уравнение.

  1. Решим первое уравнение относительно y: 2(x + y) - x + 6 = 0 2x + 2y - x + 6 = 0 x + 2y + 6 = 0 2y = -x - 6 y = (-x - 6)/2 y = -0.5x - 3

  2. Теперь подставим значение y во второе уравнение: 4(x + y) - 3x - 23 = 0 4x + 4y - 3x - 23 = 0 x + 4y - 23 = 0 x + 4(-0.5x - 3) - 23 = 0 x - 2x - 12 - 23 = 0 -x - 35 = 0 x = -35

  3. Теперь найдем значение y, подставив x в уравнение для y: y = -0.5x - 3 y = -0.5(-35) - 3 y = 17.5 - 3 y = 14.5

Таким образом, решение системы уравнений: x = -35 y = 14.5

Теперь рассмотрим ваши новые вопросы:

  1. 0,9/0,09: 0,9/0,09 = 10

  2. 17/0,17: 17/0,17 = 100

  3. Найдем экстремумы функций:

a) y = 2x³ - 3x²: Для нахождения экстремумов, найдем производную функции и приравняем ее к нулю: y' = 6x² - 6x 6x² - 6x = 0 6x(x - 1) = 0

Таким образом, получаем две критические точки: x = 0 и x = 1

Теперь, чтобы определить, является ли точка экстремумом, нужно проанализировать знак производной в окрестности каждой точки:

  • Когда x < 0, y' < 0, что значит, что функция убывает в окрестности точки x = 0.
  • Когда 0 < x < 1, y' > 0, что значит, что функция возрастает в окрестности точки x = 1.
  • Когда x > 1, y' < 0, что значит, что функция убывает в окрестности точки x = 1.

Таким образом, точка (0, 0) является локальным максимумом, а точка (1, -1) - локальным минимумом.

б) y = x + 2/x² + 5: Для нахождения экстремумов, найдем производную функции и приравняем ее к нулю: y' = 1 - 4/x³ 1 - 4/x³ = 0 4/x³ = 1 x³ = 4 x = ∛4

Теперь, чтобы определить тип экстремума, проанализируем вторую производную:

y'' = 12/x⁴

Когда x = ∛4, y'' > 0, что значит, что точка (∛4, f(∛4)) является локальным минимумом.

  1. Задание с исполнителем "Утроитель": а) Из числа 3 можно получить число 30 следующим образом: 3 * 3 = 9 (прибавили 2) 9 * 3 = 27 (прибавили 2) 27 * 3 = 81 (прибавили 2) 81 * 3 = 243 (прибавили 2) 243 * 3 = 729 (прибавили 2) 729 * 3 = 2187 (прибавили 2) 2187 * 3 = 6561 (прибавили 2) 6561 * 3 = 19683 (прибавили 2) 19683 * 3 = 59049 (прибавили 2) 59049 * 3 = 177147 (прибавили 2) 177147 * 3 = 531441 (прибавили 2) 531441 * 3 = 1594323 (прибавили 2) 1594323 * 3 = 4782969 (прибавили 2) 4782969 * 3 = 14348907 (прибавили 2) 14348907 * 3 = 43046721 (прибавили 2) 43046721 * 3 = 129140163 (прибавили 2) 129140163 * 3 = 387420489 (прибавили 2) 387420489 * 3 = 1162261467 (прибавили 2) 1162261467 * 3 = 3486784401 (прибавили 2) 3486784401 * 3 = 10460353203 (прибавили 2) 10460353203 * 3 = 31381059609 (прибавили 2) 31381059609 * 3 = 94143178827 (прибавили 2) 94143178827 * 3 = 282429536481 (прибавили 2) 282429536481 * 3 = 847288609443 (прибавили 2) 847288609443 * 3 = 2541865828329 (прибавили 2) 2541865828329 * 3 = 7625597484987 (прибавили 2) 7625597484987 * 3 = 22876792081161 (прибавили 2) 22876792081161
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