Question

13 1/4 -(3 5/21 +4 6/7) =

Answer 1

Ответ:

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Пошаговое объяснение:

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Answer 2

To solve this expression, let's break it down step by step:

1. Convert all mixed numbers to improper fractions:

   • $13 \frac{1}{4} = \frac{13 \cdot 4 + 1}{4} = \frac{52 + 1}{4} = \frac{53}{4}$
   • $3 \frac{5}{21} = \frac{3 \cdot 21 + 5}{21} = \frac{63 + 5}{21} = \frac{68}{21}$
   • $4 \frac{6}{7} = \frac{4 \cdot 7 + 6}{7} = \frac{28 + 6}{7} = \frac{34}{7}$

2. Substitute the improper fractions back into the expression: $13 \frac{1}{4} - (3 \frac{5}{21} + 4 \frac{6}{7}) = \frac{53}{4} - \left(\frac{68}{21} + \frac{34}{7}\right)$

3. Find a common denominator for the fractions inside the parentheses. The common denominator for 21 and 7 is 21: $\frac{53}{4} - \left(\frac{68 \cdot 1}{21} + \frac{34 \cdot 3}{21}\right)$

4. Perform the addition inside the parentheses and simplify the fractions: $\frac{53}{4} - \left(\frac{68}{21} + \frac{102}{21}\right) = \frac{53}{4} - \frac{170}{21}$

5. To subtract the fractions with different denominators, find a common denominator. The common denominator for 4 and 21 is 84: $\frac{53 \cdot 21}{4 \cdot 21} - \frac{170 \cdot 4}{21 \cdot 4}$

6. Calculate the numerators: $\frac{1113}{84} - \frac{680}{84}$

7. Subtract the fractions: $\frac{1113 - 680}{84} = \frac{433}{84}$

So, $13 \frac{1}{4} - (3 \frac{5}{21} + 4 \frac{6}{7}) = \frac{433}{84}$.