Question

-6x +3y=0 4x + 2у=-4 2х - у=2

Answer 1

Ответ:

первое

$x = \frac{y}{2}$

$y = 2x$

второе

$x = \frac{ - y - 2}{2}$

$y = - 2x - 2$

третье

$x = \frac{y + 2}{2}$

$y = 2x - 2$

Answer 2

To solve the system of equations:

-6x + 3y = 0 ...(1) 4x + 2y = -4 ...(2) 2x - y = 2 ...(3)

We can use the method of substitution or elimination to find the values of x and y. Let's use the method of substitution:

From equation (3), we can express y in terms of x: y = 2x - 2

Substituting this value of y into equation (1): -6x + 3(2x - 2) = 0 -6x + 6x - 6 = 0 -6 = 0

The equation -6 = 0 is not true, which means the system of equations is inconsistent. There is no solution that satisfies all three equations simultaneously.