Question

X² – 3x +2=0??????????​

Answer 1

Ответ:

D=9-8=1

x1=(3+1)/2=2

x2=(3-1)/2=1

Answer 2

It seems like you've provided a quadratic equation: $x^2 - 3x + 2 = 0$. To solve for $x$, we can use the quadratic formula or factor the equation.

Method 1: Quadratic Formula The quadratic formula is given by: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In your equation $x^2 - 3x + 2 = 0$, the coefficients are:

• $a = 1$ (coefficient of $x^2$)
• $b = -3$ (coefficient of $x$)
• $c = 2$ (constant term)

Plugging these values into the quadratic formula:

$x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4 \cdot 1 \cdot 2}}{2 \cdot 1}$ $x = \frac{3 \pm \sqrt{9 - 8}}{2}$ $x = \frac{3 \pm \sqrt{1}}{2}$

Since the square root of 1 is 1:

$x = \frac{3 \pm 1}{2}$

This gives us two solutions: $x_1 = \frac{3 + 1}{2} = 2$ $x_2 = \frac{3 - 1}{2} = 1$

So, the solutions to the equation $x^2 - 3x + 2 = 0$ are $x = 2$ and $x = 1$.

Method 2: Factoring Another way to solve this equation is by factoring: $x^2 - 3x + 2 = 0$ $(x - 2)(x - 1) = 0$

Now, using the zero product property, we can set each factor equal to zero:

$x - 2 = 0$ implies $x = 2$

$x - 1 = 0$ implies $x = 1$

Again, the solutions are $x = 2$ and $x = 1$.

Both methods lead to the same solutions: $x = 2$ and $x = 1$.