Question

(система)2х-3у=-42х+у=4​

Answer 1

{2x-3y = -4
{2x+y = 4

{2x-3y = -4
{-2x-y = -4
Сложу эти уравнения (знак плюс слева от фигурной скобки)
-4y = -8
y = 2
Подставлю y во второе уравнение;
2x + 2 = 4
x = 1
(x, y) = (1, 2)

Проверка:
{2*1-3*2 = -4
{2*1+2 = 4

{-4 = -4
{4 = 4

Ответ: (x, y) = (1, 2)

Answer 2

To solve the system of equations:

(1) 2x - 3y = -4 (2) -2x + y = 4

We can use the method of substitution or elimination. I'll demonstrate the elimination method here:

Let's multiply equation (2) by 3 to make the coefficients of y in both equations equal:

(2) -2x + y = 4 => 6(-2x + y) = 6(4) => -12x + 3y = 24

Now we have the following system:

(1) 2x - 3y = -4 (3) -12x + 3y = 24

Adding equations (1) and (3) eliminates the y terms:

(1) 2x - 3y = -4 (3) -12x + 3y = 24

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         -10x = 20

Divide both sides of the equation by -10:

-10x / -10 = 20 / -10 x = -2

Substituting the value of x back into equation (1):

2(-2) - 3y = -4 -4 - 3y = -4 -3y = 0 y = 0

Therefore, the solution to the system of equations is x = -2 and y = 0.