Question

А)а⁶ • а¹²Б) а¹⁶:а¹¹В) (а⁷)³Г) (4а⁵)³Д) 7⁶•7¹⁴ : 7¹⁸Е) 25³•2⁶ : 10⁴​

Answer 1

Ответ:A)a^6+12

Б)a^16-11

В)а^7•3

Г)64а^5•3

Д)7^6+14-18

Е)подними в степени и сделай всё остальное

Answer 2

Let's simplify each expression step by step:

A) а⁶ • а¹² When multiplying two powers with the same base, you add their exponents: а⁶ • а¹² = а^(6+12) = а¹⁸

B) а¹⁶ : а¹¹ When dividing two powers with the same base, you subtract the exponent of the denominator from the exponent of the numerator: а¹⁶ : а¹¹ = а^(16-11) = а⁵

C) (а⁷)³ When raising a power to another power, you multiply the exponents: (а⁷)³ = а^(7*3) = а²¹

D) (4а⁵)³ When raising a product to a power, you raise each factor to that power: (4а⁵)³ = 4³ * (а⁵)³ = 64 * а^(5*3) = 64а¹⁵

E) 7⁶•7¹⁴ : 7¹⁸ When dividing powers with the same base, you subtract the exponent of the denominator from the exponent of the numerator: 7⁶•7¹⁴ : 7¹⁸ = 7^(6+14-18) = 7² = 49

F) 25³•2⁶ : 10⁴ 25³•2⁶ : 10⁴ = (5²)³ • 2⁶ : (2•5)⁴ = 5^(2*3) • 2⁶ : 2⁴ • 5⁴ = 5⁶ • 2² : 5⁴ = 5^(6-4) • 2² = 5² • 2² = 25 • 4 = 100

Therefore: A) а⁶ • а¹² = а¹⁸ B) а¹⁶ : а¹¹ = а⁵ C) (а⁷)³ = а²¹ D) (4а⁵)³ = 64а¹⁵ E) 7⁶•7¹⁴ : 7¹⁸ = 49 F) 25³•2⁶ : 10⁴ = 100